http://scholar-vit.livejournal.com/ ([identity profile] scholar-vit.livejournal.com) wrote in [personal profile] annageish 2011-10-10 03:29 pm (UTC)

Увы, но то, что Вы видите решку, вносит асимметрию в условия задачи.

Кстати, предположим, что монет только две: РР и ОР. Вы видите решку. Какова вероятность орла под ней?

Ответ: 1/2*1/2:(1/2+1/2*1/2) = 1/3.
(31 comments)

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